ProjectEuler Solved Question-1 ( with two Solutions)

  If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.


Find the sum of all the multiples of 3 or 5 below 1000.




# first way
def divisible_by_under(limit, divs):
    return (i for i in  range(limit) if any(i % div == 0 for div in divs))
print(sum(divisible_by_under(10, (3, 5))))

# 2nd way
print(sum([i for i in range(10) if i%3==0 or i%5==0]))

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