Merge The Tools Hackerrank Solution

 Consider the following:

  • A string, , of length  where .
  • An integer, , where  is a factor of .

We can split  into  substrings where each subtring, , consists of a contiguous block of  characters in . Then, use each  to create string  such that:

  • The characters in  are a subsequence of the characters in .
  • Any repeat occurrence of a character is removed from the string such that each character in  occurs exactly once. In other words, if the character at some index  in  occurs at a previous index  in , then do not include the character in string .

Given  and , print  lines where each line  denotes string .

Example

There are three substrings of length  to consider: 'AAA', 'BCA' and 'DDE'. The first substring is all 'A' characters, so . The second substring has all distinct characters, so . The third substring has  different characters, so . Note that a subsequence maintains the original order of characters encountered. The order of characters in each subsequence shown is important.

Function Description

Complete the merge_the_tools function in the editor below.

merge_the_tools has the following parameters:

  • string s: the string to analyze
  • int k: the size of substrings to analyze

Prints

Print each subsequence on a new line. There will be  of them. No return value is expected.

Input Format

The first line contains a single string, .
The second line contains an integer, , the length of each substring.

Constraints

  • , where  is the length of 
  • It is guaranteed that  is a multiple of .

Sample Input

STDIN       Function
-----       --------
AABCAAADA   s = 'AABCAAADA'
3           k = 3

Sample Output

AB
CA
AD

Explanation

Split  into  equal parts of length . Convert each  to  by removing any subsequent occurrences of non-distinct characters in :

Print each  on a new line.



## Solution:---

def merge_the_tools(string, k):
    # your code goes here
    
    for i in range(0,len(string),k):
        
    
        a=string[i:i+k]
    
        b=set()
        for x in a:
            if x not in b:
                 
                print(x,end=''
                b.add(x) 
        print()
                
         
                 
         
            
    
    
    
    
if __name__ == '__main__':

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